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Added get_permission_namespace_label helper function

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Roberto Rosario
2011-10-27 07:45:26 -04:00
parent 3f9e79f0bc
commit 548abaaf70
1 changed files with 5 additions and 1 deletions
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4
apps/permissions/api.py
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@@ -62,6 +62,10 @@ def get_permission_label(permission):
return unicode(permission_titles.get('%s.%s' % (permission.namespace, permission.name), permission.label)) return unicode(permission_titles.get('%s.%s' % (permission.namespace, permission.name), permission.label))
def get_permission_namespace_label(permission):
return namespace_titles[permission.namespace] if permission.namespace in namespace_titles else permission.namespace
register_permission(PERMISSION_ROLE_VIEW) register_permission(PERMISSION_ROLE_VIEW)
register_permission(PERMISSION_ROLE_EDIT) register_permission(PERMISSION_ROLE_EDIT)
register_permission(PERMISSION_ROLE_CREATE) register_permission(PERMISSION_ROLE_CREATE)