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Return translatable permission labels and permission namespace label straight from the model

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This commit is contained in:
Roberto Rosario
2011-11-03 12:03:47 -04:00
parent 8a27b1866b
commit 2b3629f899
1 changed files with 8 additions and 1 deletions
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9
apps/permissions/models.py
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@@ -5,6 +5,7 @@ from django.contrib.contenttypes import generic
from django.contrib.auth.models import User
from permissions.managers import RoleMemberManager, PermissionManager
from permissions.runtime import namespace_titles, permission_titles
class Permission(models.Model):
@@ -21,7 +22,7 @@ class Permission(models.Model):
verbose_name_plural = _(u'permissions')
def __unicode__(self):
return '%s: %s' % (self.namespace, self.label)
return u'%s: %s' % (self.get_namespace_label(), self.get_label())
def get_holders(self):
return [holder.holder_object for holder in self.permissionholder_set.all()]
@@ -60,6 +61,12 @@ class Permission(models.Model):
except PermissionHolder.DoesNotExist:
return False
def get_label(self):
return unicode(permission_titles.get('%s.%s' % (self.namespace, self.name), self.label))
def get_namespace_label(self):
return unicode(namespace_titles[self.namespace]) if self.namespace in namespace_titles else self.namespace
class PermissionHolder(models.Model):
permission = models.ForeignKey(Permission, verbose_name=_(u'permission'))